Coordination Dilemma (JEE)

Chemistry Level 3

The total number of possible isomers of the compound [ C u X I I ( N H X 3 ) X 4 ] [ P t X I I C l X 4 ] [ \ce{Cu^{II} (NH_3)_4 } ] [ \ce{Pt^{II}Cl_4} ] (including itself) are:

3 4 5 6 None of the above.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

1. [ C u I I ( N H 3 ) 4 ] [ P t I I C l 4 ] 1. [Cu^{II}(NH_3)_4][Pt^{II}Cl_4]

2. [ P t I I ( N H 3 ) 4 ] [ C u I I C l 4 ] 2. [Pt^{II}(NH_3)_4][Cu^{II}Cl_4]

3. [ P t I I ( N H 3 ) 3 C l ] [ C u I I C l 3 ( N H 3 ) ] 3. [Pt^{II}(NH_3)_3Cl][Cu^{II}Cl_3(NH_3)]

4. [ C u I I ( N H 3 ) 3 C l ] [ P t I I C l 3 ( N H 3 ) ] 4. [Cu^{II}(NH_3)_3Cl][Pt^{II}Cl_3(NH_3)]

The compound [ C u I I ( N H 3 ) 2 C l 2 ] [ P t I I C l 2 ( N H 3 ) 2 ] [Cu^{II}(NH_3)_2Cl_2][Pt^{II}Cl_2(NH_3)_2] does not exist as there is no net charge on either of the coordination spheres.

Our teacher gave this problem in class.

Anurag hooda - 2 years, 5 months ago

It appeared in one of fiitjee's tests!!

Kunal Gupta - 6 years, 1 month ago

Oh!. Now I realized it. It was really foolish of me to report this beautiful problem.

Prakhar Gupta - 6 years, 1 month ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...