Copying Files In Different Ways. Which Will Take Less Time ?

If we copy entire folder it will take 26.055 sec $60=1\times t_{1}+\frac{1}{2}\times 0.1\times t_{1}^{2}\; =>t_{1}=26.055\: sec$ If we copy separately it will take 48.3 sec $6=1\times \left ( \frac{t_{2}}{10} \right )+\frac{1}{2}\times 0.1\times \left ( \frac{t_{2}}{10} \right )^{2}\; =>t_{2}=48.3\: sec$ so, we should copy entire folder

when the file size increases the writing speed have much time to increase its speed. So copy all files together wil make it faster..

By copying the entire folder we would have:

$60 = 0 + 1t + \frac{1}{2} \times \frac{t^{2}}{10}$

$t^{2} + 20t - 1200 = 0$

$t = \frac{-20 \pm \sqrt{400 + 4800}}{2}$

$t \cong \frac{-20 + 72}{2}$

$t \cong 26$

And then by copying file by file:

$6 = 0 + 1t + \frac{1}{2} \times \frac{t^{2}}{10}$

$t^{2} + 20t - 120 = 0$

$t = \frac{-20 \pm \sqrt{400 + 480}}{2}$

$t \cong \frac{-20 + 29}{2}$

$t \cong 4.5 (\times 10) = 45$

So, copying the entire folder once is faster

ANALOGY: you have a distance of 60 m to cover. After every 6m , there is a mark .your initial velocity is 1m/sec and your acceleration is 0.1 m/s^2. There are two ways- PROCESS 1) You start with 1m/sec and keep on accelerating with 0.1m/s^2 till 6 m, where you stop( completion of copying of 1 file). Then , again you start from 1m/sec and accelerate with 0.1m/s^2 till you reach the second mark. And so on until you cover the entire journey. PROCESS 2) You start with 1m/s and accelerate with 0.1m/s^2 till you reach 60m , without stopping anywhere(copying the entire folder). Now which process leads you to the destination quickly? Obviously the second one. So copying the entire folder wiuld be quicker in this case.

i solve this with pure logic,no calculation needed

This can be done using kinematics. Lets see the the first option: distance covered should be 6, the initial speed is 1, the acceleration is 0.1 and the total number of files is 10. Using formula D=ut+0.5at^2, where D is distance, initial velocity is u, a is acceleration and t is time. Put in the values and you get a quadratic equation, which when solved gives you the answer of 48.3. Now consider the second option: where distance is 60, while all the other values are same, once again apply the above stated formula and get the value of 26.1. Hence, it can be deduced that copying the entire folder is the faster method.

Copying the entire folder needs us to only click the PC once.

Copying it separately needs us to click x number of times.

Since both procedure involves the same amount of memory, COPYING THE ENTIRE FOLDER ONCE would be faster.

when it take time by passing every folder then it is easy to pass hole document as a folder .

If you copy a folder, the copying speed increasing until the last file. If you do it separately, it will copy part by part, so take more time

Copying the entire folder we will have more time to have the increases of the speed. And so, at the end we will have an big speed for a long time. In the other case, we would have a low speed for al the tme. look for this problem... https://brilliant.org/community-problem/downloading/?group=BTXG9a06ab0O

here we ca take the distance as 60 and time as t intial folder copying as one and acc as 0.1 we can apply s=ut+0.5at^2 as per cpy one folder the time t becomes t2/10 sp cpy whole folder is good

if we copy entire folder then average copying speed will be more than that of copying separately. Because when we start copying one by one maximum copying speed will be less because of small time of copying one file and for another file copying speed will again start from 1MB/sec. so average speed will be less. But when we decide to copy entire folder copying time will be more than copying single file so maximum copying speed will be more because acceleration in both case is same, this yields more average copying speed that of previous case. Since average copying speed in 2nd case is more so time consumption will be less.

copy together will take less time

When whole folder is copied more time is given for the speed to increase.