Victor Loh contributes correction tapes for the class to use every day :P. On the first day, he contributed 1/6 of his total contribution. On the next day, he contributed 1/5 of the remainder. The next day he contributed 1/3 of the remainder, and on the last day he contributed 8 correction tapes :P However an elf (or something like that) mysteriously seized 10 correction tapes, and given that Victor had to get a correction tape each for each classmate, how many correction tapes did Victor need?
Notes and assumptions---- 1. Victor's class has 25 students, inclusive of him. He needs a correction tape for himself. 2. Thanks Victor Loh even though I didn't get permission to use his name...
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Hi Samuel! Thanks for posting a problem all about me!
Anyway, here's the solution:
Let the number of correction tapes that Victor prepared at first be 1 8 x .
On the first day, he gave out 6 1 × 1 8 x = 3 x correction tapes.
On the second day, he gave out 5 1 × ( 1 8 − 3 ) x = 3 x correction tapes.
On the third day, he gave out 3 1 × ( 1 8 − 3 − 3 ) x = 4 x correction tapes.
On the fourth day, he gave out 8 correction tapes.
In total, he gave out 3 x + 3 x + 4 x + 8 = 1 8 x correction tapes.
1 0 x + 8 = 1 8 x
8 x = 8
x = 1
Hence, he prepared 1 8 ( 1 ) = 1 8 correction tapes. However, the elf took away 1 0 correction tapes, hence he is left with 8 . The number of correction tapes remaining to give out to everybody in his class is 2 5 − 8 = 1 7 .