Count 'em All 20!

The figure above shows an 8 × 8 8\times8 grid but with a hole in it.

Count the total number of quadrilaterals in the grid above.

Clarifications :

  • A quadrilateral is a polygon that has 4 sides.
  • The quadrilaterals cannot contain the hole! I don't like holes.

This is one part of Quadrilatorics .


The answer is 896.

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1 solution

X X
Jul 21, 2018

All of the rectangles(including those containing the hole): ( 1 + 2 + . . . + 8 ) 2 = 1296 (1+2+...+8)^2=1296

The ones containing the hole:The rectangle is formed with 2 horizontal lines and 2 vertical lines.

One of the horizontal lines must be on the left of the hole(4 ways),the other is on the right of the hole(5 ways).

One of the vertical lines must be above the hole(5 ways),the other is below the hole(4 ways).

So there are 4 × 5 × 5 × 4 = 400 4\times 5\times 5\times 4=400 rectangles containing the hole.

Hence,there are 1296 400 = 896 1296-400=896 rectangles not containing the hole.

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