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Each letter in the word “ENCYCLOPEDIA” were written in 1 inch by 1 inch tiles. These tiles were put in a box. If two tiles are drawn at random without replacement, what is the probability that the two letters are the same?

1 6 \frac{1}{6} 1 33 \frac{1}{33} 1 132 \frac{1}{132} 2 33 \frac{2}{33}

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1 solution

There are 2-C’s and 2-E’s in the word. The letters that can be drawn are either 2-C or 2-E.

P = P = ( 2 12 ) ( (\frac{2}{12})( 1 11 ) + ( \frac{1}{11})+( 2 12 ) ( \frac{2}{12})( 1 11 ) \frac{1}{11}) = = 1 33 \frac{1}{33}

Alternate Solution:

P = P = 2 C 2 + 2 C 2 12 C 2 \frac{2C2 + 2C2}{12C2} = = 1 33 \frac{1}{33}

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