Count the squares

First, we make a list of all widths that can be produced by combining one, two, or more adjacent vertical strips. $\begin{array}{r|cccccc} \hline \text{one strip} & 1 & 2 & 1 & 3 & 1 & 2 \\ \text{two strips} & 3 & 3 & 4 & 4 & 3 \\ \text{three strips} & 4 & 6 & 5 & 6 \\ \text{four strips} & 7 & 7 & 7 \\ \text{five strips} & 8 & 9 \\ \text{six strips} & 10 \\ \hline \end{array}$ Likewise, we list all heights that can be produced by combining horizontal strips. $\begin{array}{r|cccccc} \hline \text{one strip} & 1 & 2 & 1 & 2 & 2 & 2 \\ \text{two strips} & 3 & 3 & 3 & 4 & 4 \\ \text{three strips} & 4 & 5 & 5 & 6 \\ \text{four strips} & 6 & 7 & 7 \\ \text{five strips} & 8 & 9 \\ \text{six strips} & 10 \\ \hline \end{array}$ Squares are formed wherever a vertical strip and a horizontal strip of equal dimensions intersect. Hence we add $\begin{array}{r|cc|c} \text{size} & \text{ver. strips} & \text{hor. strips} & \text{squares} \\ \hline 1 & 3 & 2 & 6 \\ 2 & 2 & 4 & 8 \\ 3 & 4 & 3 & 12 \\ 4 & 3 & 3 & 9 \\ 5 & 1 & 2 & 2 \\ 6 & 2 & 2 & 4 \\ 7 & 3 & 2 & 6 \\ 8 & 1 & 1 & 1 \\ 9 & 1 & 1 & 1 \\ 10 & 1 & 1 & 1 \\ \hline & & & \boxed{50}\end{array}$ Thus we see that there is a total of $\boxed{50}$ squares in the diagram.

there is a square 10x10, and u can make an square 1x1 (minimum integer size of x measuring in this case) and it took you 2 meters^2 for wich one, so just divide 100/2 and u get 50