By checking the family tree, Zilly Zonkers knows that his family has avoided inbreeding. If he were to trace through 5 previous generations to his great - great - great - grand parents, how many ancestors would he have counted?
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It's much easier with the picure LOL
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loll
lolz :D yes
This confused me because I focused on "Great great grandparents", which takes us to 5 generations (including Zilly) and gives 30 ancestors.
To go to 5 PREVIOUS generations, you would get to "Great great great grandparents" it seems to me.
So the statement of the problem seems contradictory.
Am I mixed up somehow?
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The question states that Zilly looked through 5 previous generations, with the key word being "previous", so we know to look at the 5 prior to Zilly, rather than the 4 prior and Zilly.
Hopefully this helps clear things up.
No, you're correct. I included Zilly to, for he counts as one of the generations.
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Wait, I just reread the question, and it said previous generations. I'm such a fool! How did I not notice that!
Yes, I got 30 originally because of the problem wording. Maybe this should be specified more clearly in the problem.
Steven I agree. If you stop at great-great-grandparents, you have 2 parents + 4 grandparents + 8 great-grandparents + 16 great-great-grandparents = 30 ancestors.
i'm not sure!!...62
62
62
I doubled the amount all the way up to the 5th generation and then I added all the numbers that I found. So it was 2+4+8+16+32 which gave me a total of 62. I dont think it was the "smartacular" way but I just wanted to share how I got my answer.
same here,62
Its a geometric sequence with first term(x)=2, number of terms(n)=5 and common rate(r)=2 * since for every parent we have 2 grandparents(given the condition of no inbreeding)*. The formula for this is x{(1-r^n)/(1-r)}, if you followed PEMDAS you'll get 62 by substituting the givens. :)
That does make it somewhat easier but I don't think that was the author's intention. :)
This problem seems overrated... Just saying..
You have a family tree with two parents. Each parent gave birth to two children. It repeats with these children, over, and over, and over, again. (observe the picture)
So you have: 2 , which is from the two great parents (let's just leave it at that) and two + two babies, from the above description, which is 2 2 . Hmmm.... If we continue, and these four 'parents' go on to create two babies each, it becomes 8 , or 2 3 . It continues on until we reach five generations.
So our answer is, by adding up the ancestors, or "parents", we get 2 + 4 + 8 + 1 6 + 3 2 , which is 2 + 2 0 + 4 0 , which is finally 6 2 Ans.
It's a really simple geometric progression that goes multiplying by 2
SIMPLY , a progression of 32, 16, 8... so on till 2 ... find the sigma. is 62
for father 2.....for grandfather 2 2.....for great grandfather 4 2......then 8 2+16 2.sum=62
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In the fifth generation we have 2 5 ancestors
In the fourth generation as each previous ancestor had only one child we have to the number of people from that generation is 2 2 5 = 2 4
In the third generation, similarly we have 2 3 ancestors
In the second generation we have 2 2 ancestors
And finally, in the first generation we have 2 ancestors
Note: we considered the previous generations and Zilly is not an ancestor.
Soon we have
2 + 2 2 + 2 3 + 2 4 + 2 5 = ( 1 + 2 + 2 2 + 2 3 + 2 4 + 2 5 ) − 1 = ( 2 6 − 1 ) − 1 = 6 3 − 1 = 6 2 ancestors.