Crazy Calculus 6

Calculus Level 3

An air force plane is ascending vertically at the rate of 100 km/hr 100\text{ km/hr} . If the radius of the Earth is R km R \text{ km} , how fast is the area of the Earth visible from the plane increasing at 3 minutes after it started ascending?

Take visible area A = 2 π R 2 H R + H A=\dfrac { 2\pi R^ 2H }{ R+H } , where H H is the height of the plane (in km \text{km} ) above the Earth.

P : 200 π r 3 ( R + 5 ) 2 \frac { 200\pi r^ 3 }{ (R+5)^ 2 } k m 2 h \frac { km^ 2 }{ h }

Q : 200 π r 3 ( R + 5 ) \frac { 200\pi r^ 3 }{ (R+5) } k m 2 h \frac { km^ 2 }{ h }

R : 400 π r 3 ( R + 5 ) \frac { 400\pi r^ 3 }{ (R+5) } k m 2 h \frac { km^ 2 }{ h }

S : 400 π r 3 ( R + 5 ) 2 \frac { 400\pi r^ 3 }{ (R+5)^ 2 } k m 2 h \frac { km^ 2 }{ h }

s q p r

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1 solution

Jatin Chanchlani
Jul 15, 2016

1 pending report

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