Crazy dog

Algebra Level 3

Boy with his dog waiting for her girl under the tree. When his dog see the girl coming he started running from boy to girl and girl to boy until boy and girl kissed under the tree. If dog starts running when they were 100m away and If velocity of girl toward tree is 0.5m/s. Then find the distance travel by the dog? If speed of dog is 5m/s.

0.2km 1km 5km 100m

Dienever Gupta by Dienever Gupta , 26, India

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2 solutions

Because the time for the girl and dog moving is the same. So dog moves the distance is: 100 × 5 0.5 = 1000 m = 1 k m 100 \times \frac{5}{0.5}=1000m=\boxed{1km}

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Dienever Gupta
Jul 4, 2014

{Time girl take to reach the boy= DISTANCE/SPEED=100/0.5 sec= 200 second = Time of dog keep running}

{Distance travel by dog= SPEEDXTIME=5X200 meter =1000 meter(1KM)}

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