Crazy polynomial remainder!

Level 2

Let a polynomial P( x x ) = x 5 x^{5} + x 4 x^{4} + x 3 x^{3} + x 2 x^{2} + x x + 1. If P( x 6 x^{6} ) is divided by P( x x ), find its remainder.


The answer is 6.

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1 solution

Hugh Sir
Oct 9, 2018

P ( x ) = x 5 + x 4 + x 3 + x 2 + x + 1 P(x) = x^{5}+x^{4}+x^{3}+x^{2}+x+1

P ( x 6 ) = x 30 + x 24 + x 18 + x 12 + x 6 + 1 P(x^{6}) = x^{30}+x^{24}+x^{18}+x^{12}+x^{6}+1

P ( x 6 ) = ( x 30 1 ) + ( x 24 1 ) + ( x 18 1 ) + ( x 12 1 ) + ( x 6 1 ) + 6 P(x^{6}) = (x^{30}-1)+(x^{24}-1)+(x^{18}-1)+(x^{12}-1)+(x^{6}-1)+6

Notice that ( x 30 1 ) (x^{30}-1) is divisible by ( x 6 1 ) (x^{6}-1) .

This is also true for ( x 24 1 ) (x^{24}-1) , ( x 18 1 ) (x^{18}-1) , ( x 12 1 ) (x^{12}-1) and ( x 6 1 ) (x^{6}-1) .

Also notice that ( x 6 1 ) (x^{6}-1) is divisible by P ( x ) P(x) .

Hence, the remainder when P ( x 6 ) P(x^{6}) is divided by P ( x ) P(x) is 6 6 .

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