Crazy Products

If seven consecutive numbers are chosen from 1 to 50, how many products ends with at least two zeros?


The answer is 20.

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1 solution

Timothy Wong
Apr 26, 2014

In order to make 2 zeros at the end, we need 100 as a factor which is equal to 2 2 × 5 2 2^2 \times 5^2

( 4 10 ) , ( 5 11 ) , ( 9 15 ) , ( 10 16 ) , ( 14 20 ) , ( 15 21 ) , ( 19 25 ) , ( 20 26 ) , ( 24 30 ) , ( 25 31 ) , (4-10), (5-11), (9-15), (10-16), (14-20), (15-21), (19-25), (20-26), (24-30), (25-31),

( 29 35 ) , ( 30 36 ) , ( 34 40 ) , ( 35 41 ) , ( 39 45 ) , ( 40 46 ) , ( 44 50 ) = 17 p o s s i b l e p r o d u c t s (29-35), (30-36), (34-40), (35-41), (39-45), (40-46), (44-50) = \boxed{17 possible products}

Why doesn't ( 21 27 ) (21-27) work? Did you forget about 25 = 5 2 25 = 5^2 ?

Calvin Lin Staff - 7 years, 1 month ago

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Oops... Sorry... Gonna update it.. The answer must be 20... (Adding (21-27), (22-28), and (23-29))

Timothy Wong - 7 years, 1 month ago

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