Cricket match probability

Probability Level 1

In a cricket match a batsman hits a boundary 6 times out of thirty balls he plays, find the probability that he doesn't hit a boundary.

1 3 \frac13 4 5 \frac45 3 8 \frac38 2 5 \frac25

Anubhav Chakraborty by Anubhav Chakraborty , 14, India

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

4 solutions

6 30 \frac{6}{30} = 1 5 \frac{1}{5}

1 − 1 - 1 5 \frac{1}{5} = = 4 5 \frac{4}{5}

1 Helpful 0 Interesting 0 Brilliant 0 Confused
Mahdi Raza
Jun 20, 2020

P ( No Boundary ) = 1 − P ( Boundary ) P ( No Boundary ) = 1 − 6 30 P ( No Boundary ) = 4 5 \begin{aligned} P(\text{No Boundary}) &= 1 - P(\text{Boundary}) \\ P(\text{No Boundary}) &= 1 - \dfrac{6}{30} \\ P(\text{No Boundary}) &= \boxed{\dfrac{4}{5}} \end{aligned}

1 Helpful 0 Interesting 0 Brilliant 1 Confused

Let P is the event of hitting the boundary

n(P)=6

Let Q be the event of not hitting the boundary

n(Q)=30- n(P)=24

probability of not hitting the boundary= n(Q)/30 =24/30 = 4/5

1 Helpful 0 Interesting 0 Brilliant 0 Confused

Even if you calculate the number of boundaries that the batsman hit you can easily understand the number he didn't hit a boundary is the opposite then you can subtract 6(the number of boundaryies that the batsman hit) from 30( the number of balls he attempted) You get 24(the number of times he didn't hit a boundary) by the number of balls he attempted which is 30 = 24/30 which simplifies to the answer 4/5

Anubhav Chakraborty - 11 months, 3 weeks ago
Abhinav C
Jun 23, 2020

if the batsman hits 6/30 boundaries .

he does not hit 24/30 boundaries.

24/30=4/5

so the answer is 4/5

0 Helpful 0 Interesting 0 Brilliant 0 Confused

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...