Critical s i n , c o s sin,cos

Geometry Level 3

sin x + sin y = 1 cos x + cos y = 0 \sin x+\sin y=1\\ \cos x+\cos y=0

If x , y R + x,y\in \mathbb R^{+}

What's the minimum value of x + y = ? ? \large x+y=??

None of these 0 π 4 \frac{\pi}{4} π 2 \frac{\pi}{2} π \pi

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Md Mehedi Hasan
Nov 19, 2017

s i n x + s i n y = 1 2 s i n x + y 2 c o s x y 2 = 1............. ( i ) sinx+siny=1\\2sin\frac{x+y}{2}cos\frac{x-y}{2}=1.............(i)

Again c o s x + c o s y = 0 2 c o s x + y 2 c o s x y 2 = 0............. ( i i ) cosx+cosy=0\\2cos\frac{x+y}{2}cos\frac{x-y}{2}=0.............(ii)

From ( i i ) (ii) , c o s x y 2 0 cos\frac{x-y}{2}\neq0 because, if this right then it doesn't satisfy ( i ) (i) equation.

Then,

c o s x + y 2 = 0 = c o s π 2 x + y 2 = π 2 x + y = π cos\frac{x+y}{2}=0=cos\frac{\pi}{2}\\\frac{x+y}{2}=\frac{\pi}{2}\\\therefore x+y=\boxed{\pi}

Bro...your solution has a bit of error...if sinx = siny =1, then sinx + siny =2, but have only given sinx + siny=1...

I guess you should make it sinx + siny... you have accidentally written = in place of +

Skanda Prasad - 3 years, 6 months ago

Log in to reply

Thanks a lot. I made a mistake in typing. Now I have edited this....

Md Mehedi Hasan - 3 years, 6 months ago

Then what is x , y x, y ?

. . - 3 months, 1 week ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...