Crooked dice?

A pair of crooked 6 sided dice are rolled.

Each die has the following probabilities P ( n ) P(n) of rolling the number n n :

  • P ( 1 ) = 1 / 2 P(1) = 1/2
  • P ( 2 ) = 1 / 4 P(2) = 1/4
  • P ( 3 ) = 1 / 8 P(3) = 1/8
  • P ( 4 ) = 1 / 16 P(4) = 1/16
  • P ( 5 ) = 1 / 32 P(5) = 1/32
  • P ( 6 ) = 1 / 32 P(6) = 1/32

If the probability that they roll the same number is of the form a b \dfrac ab , where a a and b b are coprime positive integers, find a + b a+b .


More probability questions

For more Permutations quizzes.


The answer is 683.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Geoff Pilling
May 3, 2016

The probability they roll the same number is given by:

( 1 / 2 ) 2 + ( 1 / 4 ) 2 + ( 1 / 8 ) 2 + ( 1 / 16 ) 2 + ( 1 / 32 ) 2 + 1 / 32 ) 2 = 342 / 1024 = 171 / 512 (1/2)^2 + (1/4)^2 + (1/8)^2 + (1/16)^2 + (1/32)^2 + 1/32)^2 = 342/1024 = 171/512 .

And, 171 + 512 = 683 171 + 512 = \boxed{683}

Did the same way ¨ \ddot\smile

Abhay Tiwari - 5 years, 1 month ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...