Crypto 5

Vigenère cipher with $e$ as key. Vigenère cipher is like Caesar cipher, with each letter shifted a different amount.

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import math
s = 'vofipaxmtqwkxuw'
key = math.e
offset = ord('a')

t = []
for c in s:
        n = ord(c) - offset
        n = (n + 26 - int(key)) % 26 + offset
        t += [ chr(n) ]
        key = key*10 % 10

print "".join(t)

$\boxed{\mathrm{theanswerisfous}}$

I think the finals $\mathrm s$ is due to lack of precision in $\mathrm{math.\!e}$ .