The three letters before the slash are usually "com," "org," etc. Notice that the second letter in "qca" is two letters earlier in the alphabet than the third letter, like in "com." Using this, we find the Caesar cipher is +12, meaning A=M, B=N, C=O, etc. Using this on the rest of the code, the full URL is https://gist.github.com/anonymous/8207770 . The first line on that link says the answer is $\boxed{123}.$

The fourth line will tell you that you are awesome. (Though I think it would have been really funny if "Secret Message" was coded as well.)

A Shift Cipher is the same thing as a Caesar's cipher. Caesar's cipher is a rather vulnerable cipher and can easily be brute-forced as there are only 26 possible passwords or 'shifts'.The python code below prints all of the 27 possibilities,clearly the one with 12 shifts only makes sense.

def caesar(plainText, shift): 
    plainText = plainText.lower()
    for ch in plainText:
        if not ch.isalpha():return plainText
        if ch.isalpha():
            stayInAlphabet = ord(ch) + shift 
            if stayInAlphabet > ord('z'):
                stayInAlphabet -= 26
            finalLetter = chr(stayInAlphabet)
        cipherText = ""
        cipherText += finalLetter        
    return cipherText
def sc(p,s):
    return reduce(lambda x,y:x+y,[caesar(i,s) for i in p])
for i in range(1,27):
    print i,sc('qcifgsg.srl.cfu/qcifgsg/VofjofrL/QG50l/2014_H1/wbtc',i),'\n'

The shift for this shift cipher is 14. The link "uwgh.uwhvip.qca/obcbmacig/8207770" contains "qca". It can be "com"/"edu"/"org"/.. . "com" matches with "qca" by 14 shifts. Thus we get "gist.github.com/anonymous/8207770". A B C D E F G H I J K L M N O P Q R S T U V W X Y Z O P Q R S T U V W X Y Z A B C D E F G H I J K L M N

C Code

main()

{ int i,j,x=0, a,b,k,n; char s[]="qcifgsg.srl.cfu/qcifgsg/VofjofrL/QG50l/2014_H1/wbtc", c,s2[]="uwgh.uwhvip.qca/obcbmacig/8207770"; a=strlen (s); b=strlen (s2); for(j=1; j<26; j++) { for(i=0; i<a; i++)

   { 
       if( isalpha( s[i] ) )
       {

         c=s[i]+j; 
         if(isupper(s[i]) && (s[i]+j>'Z'))
         c=c-26;

         else if(islower(s[i]) && (s[i]+j>'z'))
         c=c-26;

       }
       else 
       c=s[i];
       if(c=='e' && x==0)
           x++;
       else if(c=='d' && x==1)
           x++;   
       else if(c=='x' && x==2)
           x++;
       else x=0;

        if(x==3)
         n=j; 
   }
              }for(k=0; k<b; k++)

   { 
       if( isalpha( s2[k] ) )
       {

         c=s2[k]+n; 
         if(isupper(s2[k]) && (s2[k]+n>'Z'))
         c=c-26;

         else if(islower(s2[k]) && (s2[k]+n>'z'))
         c=c-26;

       }
       else 
       c=s2[k];
 printf("%c", c);

} }

The shift in this case is 14 because first link must be 'edx' and instead it is 'srl'. In the English alphabet, 'e' is 14 letters away from 's', so all of the other letters in the first link are 14 letters away from the decrypted phrase. Because the second link has the same shift, all of the letters are shifted by 14. So,

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shift = int(raw_input("Enter shift: ")) #14

alpha = "abcdefghijklmnopqrstuvwxyz" #English alphabet

encr = raw_input("Enter encrypted phrase: ").lower() #uwgh.uwhvip.qca/obcbmacig/8207770

decr = ""

for x in encr:
  if x in alpha:
    decr += alpha[alpha.index(x) - shift] #adds decrypted letters to a new string

print decr #gistgithubcomanonymous, the root, which is all we need: http://gist.github.com/anonymous/8207770

Using Javascript by sandy and aman

Solution Python

#    inputLink = "uwgh.uwhvip.qca/obcbmacig/8207770"
#    outputLink = ""
#
#    for s in inputLink.lower():
#        if s in l:
#            outputLink += l[l.index(s) - 14]
#        else:
#            outputLink += s
#
#    print outputLink

At first I checked domains of * $qcifgsg.srl.cfu/qcifgsg/VofjofrL/QG50l/2014_H1/wbtc$ * because we know all the domains . Here domains are .srl and .cfu. And I can match .srl to .edu with 14 backward shift and .cfu becomes .org. And this is my code:

import sys

alpha =['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']

encriptedURL= "uwgh.uwhvip.qca/obcbmacig/8207770"
for e in encriptedURL:
    if e>='a' and e<='z':
        index =(alpha.index(e)-14)%26
        if (index)<0:
            index = index*-1
        sys.stdout.write(alpha[index])
    else:
        sys.stdout.write(e)

After running this code I have Answer .