Cube, cube, cube... and another cube!
Given the equation
Find the lowest possible values for a, b, c, and d such that
= f
is the lowest whole number value possible greater than 0.
Note:
a
b
c
d
f
The answer is 18.
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1 solution
3^3+4^3+5^3=6^3 so, a=3,b=4,c=5,d=6 f=a+b+c+d, f=18