Cube Resistance Network (Part 2)

Form a resistance network with the following steps:

1) Start with a wire frame cube consisting of 12 12 line segments, each with resistance 1 Ω 1 \, \Omega
2) From a point inside the cube, draw 8 8 line segments to the vertices of the cube, each with resistance 1 Ω 1 \, \Omega
3) Connect the interior point (colored red) to the positive terminal of a battery
4) Connect 4 4 of the cube vertices (colored green) to the negative terminal of the same battery (see diagram)
5) Leave 4 4 of the cube vertices (colored black) as simple nodes connecting cube edges (see diagram)

What equivalent resistance does the network present to the battery?


The answer is 0.15135.

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1 solution

Mark Hennings
Feb 12, 2019

Firstly consider the outside cube, and the effect of shorting together the four green vertices. The diagram below shows the effect of doing this:

The next series of diagrams adds the red vertex and the additional eight resistors (four of which have combined in parallel to give a single resistance of 1 4 Ω \tfrac14\,\Omega ). Some elementary series-parallel calculations, plus two Y Y - Δ \Delta transformations, give the effective resistance as 28 185 Ω \boxed{\tfrac{28}{185}}\,\Omega .

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