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1 solution
sum of cubes from 1 to n = [n(n+1) / 2 ]^2
so , x = n(n+1) / 2
here , n = 8 so ,
x= 8 * 9 / 2
x = 36
note that here finding 'x' was same as finding sum of nos. from 1 to 8 .
so , this problem must be called as sum of natural numbers !!
we can give the proof for the sum of cubes by writing in format-
(a+1)^4 - a^4 and summation using telescopic sums