A cuboid has faces with different perimeters: 6 cm, 8 cm, and 10 cm each.
What is the volume of the cuboid?
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Let's say the cuboid has sides of lengths a , b and c . The perimeter of each of the 3 main faces are 2 a + 2 b , 2 b + 2 c , 2 c + 2 a , arbitrarily assign them to the faces given (since it is a cuboid any permutation of the faces will end with the same result)
Face 1: 2 a + 2 b = 6 ⇒ a + b = 3 ⇒ a = 3 − b
Face 2: 2 b + 2 c = 8 ⇒ b + c = 4 ⇒ c = 4 − b
Face 3: 2 c + 2 a = 1 0 ⇒ c + a = 5
Substituting the first two equations into the third, we get 3 − b + 4 − b 7 − 2 b 2 b b = 5 = 5 = 2 = 1
Hence, c = 4 − b = 4 − 1 = 3 and a = 3 − b = 3 − 1 = 2 .
Thus, the Volume = a b c = 1 ∗ 2 ∗ 3 = 6 .