Current intensity 2

If 6.25 × 1 0 19 6.25 \times 10^{19} electrons pass through the cross section of a current-carrying wire for 5 5 seconds, then what is the current intensity?

2.0 A 10.0 A 5.0 A 6.25 A

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1 solution

Shijin Appu
Jun 29, 2014

current intensity I=CHARGE (Q)/TIME TAKEN(t).
CHARGE(Q) = INTEGRAL MULTIPLE OF MAGNITUDE OF ELECTRON(N x E)
Therefore INTENSITY (I) = N x E/T
= 6.25 x 10^19 x 1.6 x 10^ -19 /5 =2.0A

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