Current Into Op-Amp Circuit

The circuit above contains an ideal operational amplifier (op-amp). At a particular instant, source voltage v s = 10 V v_s = 10 \, V , and capacitor voltages v C 1 = 1 V v_{C1} = 1 \, V and v C 2 = 2 V v_{C2} = 2 \, V .

In this instant, what is the source current i s i_s ?

Note: The op-amp has an external power supply, which is not shown


The answer is 2.333.

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1 solution

Laszlo Mihaly
Feb 20, 2018

In a feedback loop the ideal op-amp maintains zero potential difference between its input terminals. Since the + terminal is at v C 1 = 1 V v_{C1}=1V , and the output is connected to the - terminal, the output voltage is also 1V. To that value we add v C 2 = 2 V v_{C2}=2V and we get 3V, the potential at the point when the two resistors and the C 2 C_2 capacitor join each other. The voltage drop on the 3 Ω \Omega resistor is 10V-3V=7V and the current is 2.33A.

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