Curved space 1

A space station orbits the Earth on a circular orbit with a period of T = 120 T=120 minute. The station is stabilized in such a way that its main window always faces the Earth and otherwise the space craft is not rotating. All jets are off.

We set up a local system of reference so that the velocity vector of the space craft is parallel to the x x axis (forward/backward), the vector pointing from the center of the Earth to the space craft is parallel to the z z axis (up/down) and the y y axis (left/right) is perpendicular to these two. The origin of the system of reference is in the center of the space station.

An astronaut carefully places two very small steel balls 1.0 m 1.0m to the left and 1.0 m 1.0m to the right of the center ( x 1 = 0.0 m x_1=0.0m , y 1 = 1.0 m y_1=1.0m , z 1 = 0.0 m z_1=0.0m and the x 2 = 0.0 m x_2=0.0m , y 2 = 1.0 m y_2=-1.0m , z 2 = 0.0 m z_2=0.0m ) so that their velocity relative to the spacecraft is zero. How far will the balls be from each other 30 minutes later? Give your answer in meters to one decimal space.

See variations on this problem here and here and here .


The answer is 0.

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1 solution

Laszlo Mihaly
Sep 15, 2017

To a very good approximation the two balls are placed on a circular orbit around the Earth, with the same period as the space craft. The plane of all 3 orbits (for the two balls and the center of the space craft) has to go through the center of the Earth. Therefore the orbits cross each other. It takes 1/4 of the period to reach the crossing point. At that moment to distance between the balls reaches close to zero meter.

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