Curved Surface Area

Let's say you have a paper cylinder and scissors. Since we don't care about the top and the bottom, let's just assume that they are not there. Now we fetch our cutting device, and cut along the side. Easy, right? We unfold the side flat on the table to get a rectangle! One of its dimensions will be height, $h$ , and the other will be the circumference, $\pi \cdot d$ . Its area is equal to $\pi\cdot d\cdot h\approx 132$

Curved Surface Area(CSA) of Cylinder = 2(π.r.h) TT = 22/7 or 3.14

diameter = 12 => radius = 6

height= 3.5

CSA = 2(3.14* 6* 3.5) = 132

Subsituting value of radius as 12/2 =6 cm and surface area 2pi r x h we get value 132 Ans K.K.GARG,India

This three-dimensional form The required space side cylinder Area = perimeter of the base side Mud * height = 2 x 6 x 22/7 x3.5= 132

the total area = 2 (pi) (r) (h) + 2 (pi) (r^2)

and the surface area = 2 (pi) (r) (h) only = 2 (22/7) (6) (3.5) = 131.94

Just use the formula 2πrh, which yield you the value of 132

the formula for finding the c.s.a is 2 pi r*h; just put the values in places of r and h

CSA=2 * 22/7 * 6(Radius) * 3.5 (Height) =132 sq. cm

Easy. Diameter is 12. So Radius is 6 cm. Area of cylinder: 2 pi r 2 + 2 pi r h then minus the area of 2 circles and you have the area of the curved part of cylinder.

CSA = 2d*h * 22/7

It's very simple.What one is to do is to apply the C.S.A. formula of cylinder i.e. 2.pi.r.h=2×3.14×6×3.5=131.78=132

Formula for surface area of cylinder is 2piDh/2