Cut N + \mathbb{N^{+}}

Algebra Level pending

Can we divide N + \mathbb{N^{+}} into two sets A A and B B ( \big( i.e. A B = , A B = N + ) A\cap B=\emptyset, A\cup B =\mathbb{N^{+}}\big) such that

  1. no three distinct elements in A A can form an arithmetic progression;
  2. there does not exist a non-constant, infinite arithmetic progression made up of elements in B ? B?
Yes No

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

0 solutions

No explanations have been posted yet. Check back later!

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...