In an arithmetic sequence, the sixth term is twice the third term and the 30th term is 60. Find the common difference
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a 6 = 2 ∗ a 3 → a + 5 d = 2 ( a + 2 d ) a + 5 d = 2 1 + 4 d 0 = a − d ⇒ a = d
a 3 0 = 6 0 a + 2 9 d = 6 0 t h e r e f o r e : d + 2 9 d = 6 0 3 0 d = 6 0 d = 2