Daily Chemistry Problems for JEE - Day 2

Chemistry Level 2

Pure water has a reversible reduction potential of − 0.413 V -0.413 V under 1.00 a t m 1.00atm H 2 H_2 pressure. If 2 H + + 2 e − → H 2 2H^+ + 2e^- \rightarrow H_2 is considered to be the reduction, then pH of pure water is __ .

Details: Round your answer to the nearest integer.

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The answer is 7.

Sahil Bansal by Sahil Bansal , 21, India

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1 solution

Suhas Sheikh
May 29, 2018

Just use the fact That for such a cell E.m.f=-0.0591*pH Putting in values yields the closest integer as 7

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