The difference between the speeds of two trains is
. The slower train begins journey from a station and when it covers
, the faster train begins journey from the same station on a parallel line and reaches the destination
before the slower one. But if the faster train begins journey after covering
by the slower one, then it can reaches the destination
before the slower one. What is the speed (in
) of the faster train ?
Bonus question : If you can solve it, please share it with distance between the stations!
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Let the distance between the station and destination be D and the speed of the slower train be v km/hr, therefore, that of the faster train is v + 1 0 km/hr. Then we have:
⎩ ⎪ ⎨ ⎪ ⎧ v D − 1 6 0 − v + 1 0 D = 1 v D − 1 2 0 − v + 1 0 D = 2 . . . ( 1 ) . . . ( 2 )
( 2 ) − ( 1 ) : v 4 0 ⇒ v = 1 = 4 0 km/hr
⇒ The speed of the faster train is v + 1 0 = 5 0 km/hr.
For Bonus :
( 1 ) : v D − 1 6 0 − v + 1 0 D 4 0 D − 1 6 0 − 4 0 + 1 0 D 4 0 D − 4 − 5 0 D 2 0 0 D ⇒ D = 1 = 1 = 1 = 5 = 1 0 0 0 km