Danger Time

A terrorist places a bomb at a horizontal distance of 6 m 6 m from the foot of building of height 8 m 8 m . When the bomb explodes its fragments fly in all direction with a velocity of 20 m / s 20 m/s . The man on the top of the building will be in danger for a period of time t = a 11 5 t = a \sqrt \frac {11}{5} .Find the value of 100 × a 100 \times a

Details :

  • All particles after explotion falls under gravity. All other force are neglected.

  • g = 10 m / s 2 g= 10 m/s^2

  • t t the time period in which man will be in danger not not the value of time.


The answer is 200.

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