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Calculus Level 4

If f ( x ) f(x) , g ( x ) g(x) be twice differentiable function on [ 0 , 2 ] [0,2] satisfying f ( x ) f''(x) = g ( x ) g''(x) , f ( 1 ) = 2 f'(1) = 2 , g ( 1 ) = 4 g'(1) = 4 and f ( 2 ) = 3 f(2) = 3 , g ( 2 ) = 9 g(2) = 9 , then f ( x ) g ( x ) f(x) - g(x) at x = 4 x=4 equals ->

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The answer is -10.

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1 solution

Tom Engelsman
Mar 6, 2016

If f''(x) = g''(x), then integration with respect to x gives:

f'(x) = g'(x) + A

and inputting the boundary conditions f'(1) = 2, g'(1) = 4 gives A = -2, or f'(x) = g'(x) - 2.

Now integrating again gives:

f(x) = g(x) - 2x + B

and inputting f(2) = 3 , g(2) = 9 gives:

3 = 9 -2(2) + B => B = -2

or f(x) = g(x) - 2x - 2;

or f(x) - g(x) = -2(x + 1).

Hence at x = 4, (f - g)(4) = f(4) - g(4) = -2(4 + 1) = -10.

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