Darts on a dartboard!

After throwing a dart n n times at a dartboard, my percentage of hits is p p %. With my next throw I make a hit and my percentage is ( p + 1 ) (p + 1) %. Find the value of n + p n + p .

100 89 99 50 49 51 75 20

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1 solution

Rui-Xian Siew
Nov 5, 2017

After n n throws, the total hits are n p 100 \frac{np}{100} . After n + 1 n+1 throws, the total hits are n p 100 + 1 \frac{np}{100} +1 . Hence,

n p 100 + 1 n + 1 = p + 1 100 n p + 100 = n p + n + p + 1 n + p = 99 \frac{\frac{np}{100} +1}{n+1}=\frac{p+1}{100} \\ np+100=np+n+p+1 \\ \therefore n+p=99

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