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The answer is 351.

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1 solution

Himanshu Parihar
Nov 13, 2014

(x-a)(x-b)(x-c)----(x-w)"(x-x)"(x-y)(x-z)=(k-1)(k-2)(k-3)(k-4)----(k-26) ohhh! the above term will become zero then roots of this equation 1, 2,3,4,5 ,6,7,8,9,10,11,12---23,24,25,26 sum=(13X27) =351

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