A group of mathematicians are participating in a Christmas gift exchange. The organizer of the gift exchange wants to add a mathematical twist to the gift exchange, so he decides that in this gift exchange, all of the mathematicians will be numbered with a number from to . Some positive integer is chosen, and some subset of the mathematicians of size is also chosen. For each mathematician in the subset of the gift exchange, they must give a gift to the person with the number that is equivalent to the remainder when their own number plus is divided by . The mathematicians giving and receiving all the gifts must be contained within the subset. How many different values exist in the form , where is a positive prime number, and is a positive integer, such that the person with the number assignment is always in the subset?
This problem is part of The 12 Days of Math-Mas 2018
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When examined further, this problem can actually be solved fairly easily using group theory. We are given a group operation, which is addition modulo 1 0 0 0 , and a set of integers on which to act. Since this problem tells us we must include the mathematician with the 0 designation within our subset of mathematicians, we can define 0 to be the identity element of the subgroups that we are trying to find, since only subgroups will obey the given criteria within the question (the mathematicians must give a gift to the person with the number that is equivalent to the remainder when their own number plus n is divided by 1 0 0 0 , and all mathematicians giving and receiving gifts must be completely contained within the subset). By Lagrange's Theorem, we know that ∣ H ∣ ∣ G ∣ , where G is a group, and H is some subgroup. The different a values that we are trying to find are essentially the different orders of the subgroups, so we know that all a values must divide the order of G , which is 1 0 0 0 . Taking the prime factorization of 1 0 0 0 , we get 2 3 5 3 . All a values in the form p t that divide 2 3 5 3 are 2 1 , 2 2 , 2 3 , 5 1 , 5 2 , 5 3 , therefore the number of different a values is 6 .