Consider the following equation
, with greater than 0 always
Determine when n is 25 if is 0 for the given n
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3 2 5 ln ( f ′ ( x ) ) = x , f ′ ( x ) = e 3 2 5 x , f ( x ) = 3 2 5 × e 3 2 5 x + C ,so 3 2 5 f ( 1 9 5 0 ) − f ( 3 2 5 ) = e 6 − e