Decreasing powers

Assume that a, b, c, and d are positive integers such that a 5 = b 4 , c 3 = d 2 a^5 = b^4, c^3 = d^2 , and c a = 19 c - a = 19 . Determine d b d - b . Do note that this problem is from the AIME and is not my creation.


The answer is 757.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Venky Ram
Jul 22, 2014

if a^m=b^n , where a,b are reals, then there exists a real integer x such that (x^n)^m=(x^m)^n.

therefore a^5=b^4 => (x^4)^5=(x^5)^4; lly for c,d => (y^2)^3=(y^3)^2;

a=x^4, c=y^2;

and c-a=19;

the only solution satisfying this pair is (x=3,y=10);

so the values are a=81,b=243,c=100,d=1000; so d-b=757;

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...