I have an encrypted message, a. When decrypted fully, it becomes a four-letter word. Find the four-letter word. You must use the alphabet as numbers (i.e a = 1, b = 2 ..., z = 26.) Your clues are:, a = 1, I have two numbers: and , the sum of the four letters is 49, , , when you have found and , , when you have found the partially decrypted four-letter word (i.e. an example would be abbc), two further clues are: , You must show proof of you finding the four-letter word (attach it in the discussion.) Note: I have used my encryption formula: this is explained in the discussion. Note 2 : Here is my proof if any of you are confused about the wording and cannot solve it:
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My formula used in this problem is: h i g h e s t f a c t o r z ( n 1 ∗ n 2 ) / x y = b shift where: n 1 and n 2 = random integers (except negative integers), x = highest possible divisor, y = highest possible power before n 1 ∗ n 2 turns into fraction (or y 1 ), z = highest power possible (or y 2 ) and shift = encryption shift. I encrypt in three stages: 1st stage: encrypt each letter using x y n 1 ∗ n 2 and subtract any number >= 1 - afterwards I divide like this: d e n o m i n a t o r o f s h i f t 6 2 (if the shift is like 3 4 3 , I do: d e n o m i n a t o r o f s h i f t 6 2 * numerator of shift.) After that, I round the result to an integer and encrypt by that integer (if the letter is the same, I use that encrypted letter for that letter (i.e queen and encryption is azjjr, e = j (both of them)). 2nd stage: I add the encrypted letters according to their place in the normal alphabet (since I change n 1 and n 2 every time, I cannot create a sheet where each letter is specific to an encrypted letter: it depends on n 1 and n 2 .) and create a number. 3rd stage: I divide that number by h i g h e s t f a c t o r z (highest factor is any factor apart from itself and 1.) and whatever number comes out, I correspond it to the alphabet and the letter (or letters) is the final encrypted mesage.