Dedicated to Carl F. Gauss.

( M n + M n + 1 ) 2 \sum(M_n +M_{n+1})^2

Let there be two natural numbers ; S S and N N . such that : 2 p S 2^p | S and 2 q N 2^q | N , for arbitary whole numbers , p p and q q .

Let us define a new number M n M_n .

such that , M n M_n is the number formed by sum of first n + 1 n+1 and n n digits of S S and N N respectively.

Also S S and N N are j j and k k digit numbers , with provided that , ( j , k ) > n (j,k)>n , also , ( p , q ) < n (p,q) <n

Then evaluate the above summation modulo 2 p q 2^{pq}


The answer is 0.

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