Deendayal

find the greatest number that will divide 43,91&183 so as leave the same remainder in each case same......


The answer is 4.

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1 solution

Sanket Bhamwari
Aug 7, 2014

Since the required number leaves the same remainder in each case, it will exactly divide the difference between each pair of the given 3 numbers.

Hence the answer is equal to HCF(91-43,183-43,183-91) = HCF(48,140,92) = 4.

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