Definite derivative of $T_z$

Calculus Level 1

For what value of $z>0$ does the derivative of $T_z=\frac{2z-1}{2z+1}$ (with respect to $z$ ) equal to 1?

0.25 1.25 0.50 1.50

1 solution

Marta Reece
May 21, 2018

Derivative $\frac4{(2z+1)^2}=1$

Solutions $z=\frac12, z=-\frac32$

Positive solution $z=\boxed{0.5}$

I never heard of a "definite derivative." What is it?

Marta Reece - 3 years ago

I have also not heard the term definite derivatives There is typo it's solution in $z$ .

Naren Bhandari - 3 years ago

Thanks for catching it. Fixed that.

Marta Reece - 3 years ago