Evaluate : ∫ − 4 − 5 e ( x + 5 ) 2 d x + 3 ∫ 3 1 3 2 e 9 ( x − 3 2 ) 2 d x
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
for both ...if lower limit be 'a' and upper limit be 'b'
then put x=a+(b-a)u..and continue to find
I-I=0..ANS
Yaa, answer comes out to be 0
Problem Loading...
Note Loading...
Set Loading...
For 1st substitute x+5 = t
And for second one substitute 3 ((2/3) - x) = t
You will see that , they perfectly cancel each other and answe comes out to be zero! :)