If can be represented in the form where is maximum, find .
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First derivative of Riemann zeta function of a negative even integer − 2 n is given by ( see eqn (32) ):
ζ ′ ( − 2 n ) ⟹ ζ ′ ( − 2 0 1 6 ) = 2 2 n + 1 π 2 n ( − 1 ) n ζ ( 2 n + 1 ) ( 2 n ) ! = 2 2 0 1 7 π 2 0 1 6 ζ ( 2 0 1 7 ) 2 0 1 6 !
⟹ a + b + c + d = 2 0 1 6 + 2 0 1 7 + 2 + 2 0 1 6 = 6 0 5 1