Derivative of zeta function for year 2016

Calculus Level 5

A = ζ ( 2016 ) \mathfrak{A} = \zeta '(-2016) If A \mathfrak{A} can be represented in the form a ! ζ ( b ) c 2017 π d a! \dfrac{\zeta(b) }{c^{2017} \pi^{d}} where a a is maximum, find a + b + c + d a+b+c+d .


The answer is 6051.

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1 solution

Chew-Seong Cheong
Apr 23, 2016

First derivative of Riemann zeta function of a negative even integer 2 n -2n is given by ( see eqn (32) ):

ζ ( 2 n ) = ( 1 ) n ζ ( 2 n + 1 ) ( 2 n ) ! 2 2 n + 1 π 2 n ζ ( 2016 ) = ζ ( 2017 ) 2016 ! 2 2017 π 2016 \begin{aligned} \zeta' (-2n) & = \frac{(-1)^n \zeta (2n+1)(2n)!}{2^{2n+1}\pi^{2n}} \\ \implies \zeta' (-2016) & = \frac{\zeta (2017) 2016!}{2^{2017} \pi^{2016}} \end{aligned}

a + b + c + d = 2016 + 2017 + 2 + 2016 = 6051 \implies a + b + c + d = 2016+2017+2+2016 = \boxed{6051}

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