Above shows a long division. What is the sum of values of all the missing digits?
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Since the remainder is 8, the divisor is 9 since it must be larger than the remainder. Starting from the bottom, there is only one digit above 8 and the only one possible of doing it is 9 (0 is not possible because it needs the number above it to be only 8 but it is a two digit number)
So, ?? - 9 = 8; ?? = 17
at the top part again:
Since ?8 - ?? = 1
8 should be subtracted by a multiply of 9 that has a last digit of 7 which is 27
9 x 3 = 27 28 - 27 = 1
And bring down the 7
The answer is
287 / 9 = 31