∣ ∣ ∣ ∣ ∣ ∣ ∣ x 3 x 1 2 0 3 2 0 1 1 7 3 1 7 1 ∣ ∣ ∣ ∣ ∣ ∣ ∣ = 0
Find the sum of all possible values of x satisfy the equation above .
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When we open the determinant, we find that there are no x 2 term.Therefore the sum is 0 as the sum of roots of cubic equation is − x 3 c o e f f i c i e n t x 2 c o e f f i c i e n t