Determinants can be tiresome 2

Algebra Level 4

If N = n 2 ( n + 1 ) 2 ( n + 2 ) 2 ( n + 1 ) 2 ( n + 2 ) 2 ( n + 3 ) 2 ( n + 2 ) 2 ( n + 3 ) 2 ( n + 4 ) 2 N= \left | \begin{array}{ccc} n^{2} & (n+1)^{2} & (n+2)^{2} \\ (n+1)^{2} & (n+2)^{2} & (n+3)^{2} \\ (n+2)^2 & (n+3)^{2} & (n+4)^{2} \\ \end{array} \right | Find the value of N N .


The answer is -8.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Substitute 0 for n, compute the values, then solve for N.

To make the calculations just a little more small , substitute n=-2.

Aditya Chauhan - 4 years, 11 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...