Diagonal Lengths

Geometry Level 2

This isosceles trapezoid has an area of 36 3 36\sqrt{3} , with diagonals intersecting at a 12 0 120^\circ angle. How long is each diagonal?

11 11 12 12 Cannot be determined 6 3 6\sqrt{3} 5 5 5\sqrt{5}

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1 solution

We note that we can cut off an end triangle of the trapezoid, flip it and place it on the other end, converting the trapezoid into a rectangle with the same area. Let the length of a diagonal be d d . Then the area of the rectangle is given by:

Base × Height = 36 3 d cos 3 0 × d sin 3 0 = 36 3 3 4 d 2 = 36 3 d 2 = 144 d = 12 \begin{aligned} \text{Base }\times \text{ Height } & = 36 \sqrt 3 \\ d \cos 30^\circ \times d \sin 30^\circ & = 36 \sqrt 3 \\ \frac {\sqrt 3}4 d^2 & = 36\sqrt 3 \\ d^2 & = 144 \\ \implies d & = \boxed{12} \end{aligned}

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