Diagonals of a polygon

Geometry Level 2

A polygon has 44 sides. How many diagonals does the polygon have?


The answer is 902.

Einstein Nafis by Einstein Nafis , 22, Bangladesh

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3 solutions

Shivansh Tripathi
Jun 13, 2014

Use the formula D= n ( n - 3 ) / 2 , where n is the number of sides and D is the number of diagonals.Therefore, D = 44(44-3)/2 = (44×41)/2 = 22 × 41 = 902.

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I was not awarte of this formula, thanks Srivnsh Tripathi. K.K.GARG,Indiua

Krishna Garg - 6 years, 11 months ago

The formula for number of diagonals is n ( n − 3 ) 2 \color{#3D99F6}{\dfrac{n(n-3)}{2}} where n n is number of sides.So number of diagonals for this polygon is 44 ( 41 ) 2 = 22 × 41 = 902 \color{#D61F06}{\frac{44(41)}{2}=22\times41=\boxed{902}}

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Tushar Malik
Aug 15, 2014

Use the formula n(n-3)/2 and you will get the answer easily

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