A diamond expert cuts a huge cubical diamond into 960 identical diamond pieces in minimum number of cuts . If he wants to maximize the number of identical diamond pieces making same number of cuts to it. So the maximum number of such diamond pieces are:
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960 can be factorised in the nearest 3 integers as 8x10x12.
Therefore the required no of cuts is (8-1)+(10-1)+(12-1)
=27 cuts .
This can be factorised as 9x9x9.
Therefore the number of pieces are (9+1)x(9+1)x(9+1)=1000