Dice Probability given some information

You roll 2 fair dices with your eye closed, you are told "at least one of the dice is a one", what is the probability that the both dice are a 1?

1 6 \frac16 1 11 \frac1{11} 1 36 \frac1{36} 1 9 \frac19 1 12 \frac1{12}

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1 solution

John Wyatt
May 15, 2016

When you roll 2 dices there are 36 outcomes which are equally likely,

When told that one of the dices is a 1 there are 11 possible rolls that could be which are:

\begin{array}{lacara} \color{forestgreen}{1,1} & \color{skyblue}{1,2} & \color{skyblue}{1,3} & \color{skyblue}{1,4} & \color{skyblue}{1,5} & \color{skyblue}{1,6} \\ \color{skyblue}{2,1} & 2,2 & 2,3 & 2,4 & 2,5 & 2,6 \\\color{skyblue}{3,1} & 3,2 & 3,3 & 3,4 & 3,5 & 3,6 \\ \color{skyblue}{4,1} & 4,2 & 4,3 & 4,4 & 4,5 & 4,6 \\ \color{skyblue}{5,1} & 5,2 & 5,3 & 5,4 & 5,5 & 5,6 \\ \color{skyblue}{6,1} & 6,2 & 6,3 & 6,4 & 6,5 & 6,6 \\ \end{array}

Of these 11, only has both dice being 1 ==> Answer = 1 11 \frac{1}{11}

I got 6/11. Given that at least one is 1 what is the probability that is the second one which is 1..that it is how i interpreted your question so i took the whole first column of your square of results..

guido barta - 5 years, 1 month ago

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sorry - I have rephrased to "what is the probability that you rolled both dice to be a one ? "

John Wyatt - 5 years, 1 month ago

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no worries..i love bristol :)

guido barta - 5 years, 1 month ago

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