A fair 20-sided dice is rolled.
What is the probability that the roll is an even number or prime number or both?
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Didn't the question ask the probability of an even number or prime number or both? So both included?
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They are both included, but the number 2 is in both sets (2 is both even and prime).
How come 1 is not included in the set of prime numbers for the 20-sided die?
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1 is not prime by definition. It is one of those interesting 'math facts' that could have gone many ways. Because definition of prime requires divisibility by 2 numbers, 1 and itself, 1 is excluded as it is only divisible by one number. Outside of the prime thing, I like to talk about the magic of 1 in math.
If I wanted to calculate even number or prime number (so exclusive or), I would get 10/20 + 8/20 - 2* 1/20 = 16/20 right?
prime number :a number that is divisible only by itself and 1
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and also the condition that the two numbers it is divisible by are different, so 1 does not count :)
It is easier in this case to think of remaining odd numbers that are not prime in which are: 1 , 9 , 1 5
Therefore the probability of an even number or prime number has rolled is 2 0 2 0 − 3 = 2 0 1 7
Working Backwards is sometimes hugely rewarding.
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Relevant wiki: Probability - Rule of Sum
There are 1 0 even numbers on the 20-sided dice: 2 , 4 , 6 , 8 , 1 0 , 1 2 , 1 4 , 1 6 , 1 8 , 2 0
There are 8 prime numbers on the 20-sided dice: 2 , 3 , 5 , 7 , 1 1 , 1 3 , 1 7 , 1 9
There is 1 number that is both even and prime: 2
By the rule of sum, the probability that an even or prime number is rolled is 2 0 1 0 + 2 0 8 − 2 0 1 = 2 0 1 7