Dice sequence likelihood

Teuta rolled a fair six-sided die ten times and got the following sequence of results:

3 6 5 3 6 3 4 3 1 2 3 \rightarrow 6 \rightarrow 5 \rightarrow 3 \rightarrow 6 \rightarrow 3 \rightarrow 4 \rightarrow 3 \rightarrow 1 \rightarrow 2

She thought this was rather unremarkable. But how does the likelihood of this sequence compare to the likelihood of rolling ten times and getting 6 every time?

6 6 6 6 6 6 6 6 6 6 6 \rightarrow 6 \rightarrow 6 \rightarrow 6 \rightarrow 6 \rightarrow 6 \rightarrow 6 \rightarrow 6 \rightarrow 6 \rightarrow 6

The sequences are equally likely Ten 6s is less likely Ten 6s is more likely

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

Blan Morrison
Feb 22, 2018

Every possible sequence of 10 dice rolls has a 1 6 10 \frac{1}{6}^{10} chance of happening. Therefore, both sequences have an equal probability of occurring.

The reason people might get tricked by this problem is because there is a 6 × 1 6 10 = 1 6 9 6\times\frac{1}{6^{10}}=\frac{1}{6}^9 chance of a consecutive string of numbers.

Giorgos K.
Feb 22, 2018

1/6^10 each

which is1/60466176

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...